Select last row and sum of column in MySQL query

Question

My table:

date        Id  name    amount  payment
01/05/2017  01  Maxi    50000   Dec’16
01/10/2017  02  Shirly  50000   Jan’17
01/28/2017  01  Maxi    100000  Jan’17
02/12/2017  02  Shirly  50000   Feb’17

What query do I need to get this in MySQL?

Id  name    SUM(amount)  LAST(payment)
01  Maxi    1,50,000      Jan’17
02  Shirly  100,000       Feb’17

Answer 1

SELECT Id,name,SUM(amount),MAX(STR_TO_DATE(payment,'%b’%y')) AS LAST(payment) FROM TABLENAME GROUP BY Id

Try above code. Hope this will help you.

Answer 2

You can use group_concat to accumulate the payment values in a certain order, and then use substring_index to extract the first from that:

select   id, 
         name, 
         sum(amount), 
         substring_index(group_concat(payment order by date desc), ',', 1)
from     mytable
group by id

This assumes you want to take the last payment in the order by the date column. The payment column seems to be a non-date value, which will be useless to sort by.

If you need to take the last value of payment in the order of payment date, you should define that column as a date. Then you can do a simple max :

select   id, 
         name, 
         sum(amount), 
         max(payment)
from     mytable
group by id