How to pass variable as filename in subprocess.call(…) in Python?
Question
I am trying to call the following commands in Python. Basically, I want to substitute the second filename with customfilename .
customfilename = "this is me"
call ("MP4Box -add video.h264 " + customfilename, shell=True)
I get the following error:
Error - 2 input names specified, please check usage
What is the correct way to pass a variable to the call(....) command?
1 answers
solution1
0 2017-03-20 06:58:14
尝试将文件名放在字符串中并用引号引起来：
call ('MP4Box -add video.h264 "{}"'.format(customfilename), shell=True)
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