Python- dictionary initialization

Question

I need to have three names and email addresses to begin the program with. I have tried to use emailaddress = {"Drew": drew@myemail.com, "Lucie": lucie@snailmail.com, "Brodie": brodie@geemail.com} but it will give me this:

Traceback (most recent call last):

File "C:/Users/Drew/Documents/CIT 144/Email dictionary.py", line 17,

emailaddress = {"Drew": drew@myemail.com, "Lucie": lucie@snailmail.com,

NameError: name 'drew' is not defined

The program will work with emailaddress = {} , but gives that error if it has keys/values. I am new to Python and programming, so any help or explanation is appreciated greatly!!!

## This program keeps names and email addresses
# in a dictionary called emailaddress as key-value pairs.
# The program should initialize the dictionary with three
# people/email addresses. Then program should display the
# menu and loop until 5 is selected
##

def displayMenu():
    print()
    print("1) Look up email address")
    print("2) Add a name and email address")
    print("3) Change email address")
    print("4) Delete name and email address")
    print("5) End program")
    print()

emailaddress = {}
choice = 0
displayMenu()
while choice != 5:
    choice = int(input("Enter your selection (1-5): "))

    if choice == 1:
        print("Look up email address:")
        name = input("Name: ")
        if name in emailaddress:
            print("The email address is", emailaddress[name])
        else:
            print(name, "was not found")
    elif choice == 2:
        print("Add a name and email address")
        name = input("Name: ")
        email = input("Email: ")
        emailaddress[name] = email
    elif choice == 3:
        print("Change email address")
        name = input("Name: ")
        if name in emailaddress:
            email = input("Enter the new address: ")
            emailaddress[name] = email
        else:
            print(name, "was not found")
    elif choice == 4:
        print("Delete name and email address")
        name = input("Name: ")
        if name in emailaddress:
            del emailaddress[name]
        else:
            print(name, "was not found")          
    elif choice != 5:
        print("Enter a valid selection")
        displayMenu()

Answer 1

You are simply declaring your strings without quotes, making python try to interpret them and fail.

emailaddress = {"Drew": "drew@myemail.com", "Lucie": "lucie@snailmail.com", "Brodie": "brodie@geemail.com"}

will work. Notice the quotes around the email

Answer 2

emailaddress = {"Drew": drew@myemail.com, "Lucie": lucie@snailmail.com, 
"Brodie": brodie@geemail.com}

drew@myemail.com is not a string. It should be in quotations.