function haha(){
console.log('haha');
}
console.log(haha());
Prints:
haha
undefined
Is it because if you don't specify return in a function it will return undefined and this is what the second console.log is outputting?
It returns undefined
because basically your function doesn't return anything.
You could eg return a "haha" string or whatever you like.
function haha(){ console.log('haha'); return 'haha'; } console.log(haha());
Is it because if you don't specify return in a function it will return undefined and this is what the second console.log is outputting?
Yes, console.log()
prints the arguments passed to it. Arguments passed to it in the second time is the returned value of haha()
which is undefined
First console log is the due to the console.log inside haha
.
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