I have two list of dict.
students = [{'lastname': 'JAKUB', 'id': '92051048757', 'name': 'BAJOREK'},
{'lastname': 'MARIANNA', 'id': '92051861424', 'name': 'SLOTARZ'}, {'lastname':
'SZYMON', 'id': '92052033215', 'name': 'WNUK'}, {'lastname': 'WOJCIECH', 'id':
'92052877491', 'name': 'LESKO'}]
And
house = [{'id_pok': '2', 'id': '92051048757'}, {'id_pok': '24', 'id': '92051861424'}]
How to find elements that not exist in house list of dict matching by id
?
Output
output = [{'lastname':
'SZYMON', 'id': '92052033215', 'name': 'WNUK'}]
I try do that
for student in students:
for home in house:
if student['id'] != home['id']:
print student
But this only repeat list
The reason your code doesn't work is that if there's any house_id
which doesn't match a student_id
, the student
will be printed. You'd need some more logic or the any
function:
for student in students:
if not any (student['id'] == home['id'] for home in house):
print(student)
It outputs:
{'lastname': 'SZYMON', 'id': '92052033215', 'name': 'WNUK'}
{'lastname': 'WOJCIECH', 'id': '92052877491', 'name': 'LESKO'}
A more efficient solution would be to keep a set
of house_ids, and find students whose id isn't included in this set:
students = [{'lastname': 'JAKUB', 'id': '92051048757', 'name': 'BAJOREK'},
{'lastname': 'MARIANNA', 'id': '92051861424', 'name': 'SLOTARZ'}, {'lastname':
'SZYMON', 'id': '92052033215', 'name': 'WNUK'}, {'lastname': 'WOJCIECH', 'id':
'92052877491', 'name': 'LESKO'}]
house = [{'id_pok': '2', 'id': '92051048757'}, {'id_pok': '24', 'id': '92051861424'}]
house_ids = set(house_dict['id'] for house_dict in house)
result = [student for student in students if student['id'] not in house_ids]
print(result)
It outputs:
[{'lastname': 'SZYMON', 'id': '92052033215', 'name': 'WNUK'}, {'lastname': 'WOJCIECH', 'id': '92052877491', 'name': 'LESKO'}]
Note that 2 students match your description.
The reason set
enter link description here is used is that it allows much faster lookup than a list.
student_ids = set(d.get('id') for d in students)
house_ids = set(d.get('id') for d in house)
ids_not_in_house = student_ids ^ house_ids
students = [{'lastname': 'JAKUB', 'id': '92051048757', 'name': 'BAJOREK'},
{'lastname': 'MARIANNA', 'id': '92051861424', 'name': 'SLOTARZ'}, {'lastname':
'SZYMON', 'id': '92052033215', 'name': 'WNUK'}, {'lastname': 'WOJCIECH', 'id':
'92052877491', 'name': 'LESKO'}]
house = [{'id_pok': '2', 'id': '92051048757'}, {'id_pok': '24', 'id': '92051861424'}]
s = {item['id'] for item in students}
h = {item['id'] for item in house}
not_in_house_ids = s.difference(h)
not_in_house_items = [x for x in students if x['id'] in not_in_house_ids]
print (not_in_house_items)
>>>[{'name': 'WNUK', 'lastname': 'SZYMON', 'id': '92052033215'}, {'name': 'LESKO', 'lastname': 'WOJCIECH', 'id': '92052877491'}]
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