why am i getting this output(integer and double ambiguity)?

Question

#include<stdio.h>
int main()
{
int i=4;
double d=4.0;

int ii;
double dd;

scanf("%d",&ii);
scanf("%lf",&dd);

printf("%d",i+ii);
printf("%lf",(d+dd));
return 0;

}

i am providing input 12 for integer and 4.0 for double. i am getting output as 168.00000 only but there is two print statement. I don't know why?

Answer 1

The result that you are seeing is completely expected. You are likely missing the fact that you have not included a newline in your printf statements.

Following your logic, you take 12 and add 4.0 to that. The result is 16, which you print. That brings us here:

 16

You next print a floating point of dd+d . Assuming 4.0, you now print out an 8.000. Putting those together (since there was no newline) you end up with:

168.000

Answer 2

This output should be considered like

16 8.00000 

provided that you will insert a blank between the two numbers.

For example

printf("%d ",i+ii);
          ^^
printf("%lf",(d+dd));

Or you could insert the new ,line character

printf("%d\n",i+ii);
          ^^
printf("%lf\n",(d+dd));
           ^^

In this case you will get

16
8.00000 

Take into account that according to the C Standard function main without parameters shall be declared like

int main( void )
         ^^^^^^