I want to make a new document, which get all cartItems from all orders which have the same buyer
. And if it hasn't a pair (like with Leonard) it's make new doc but with status "orderId" : "merged"
.
For example: It's needed for situation, when some customer will make few different orders but I need to give only one consolidated recipe.
Collection orders
:
Input
{
"_id" : "001",
"buyer": "Sheldon"
"cartItems" : [
{
"itemName" : "Water",
"itemPrice" : 3
}
],
"totalCost" : 3
},
{
"_id" : "002",
"buyer" : "Sheldon",
"cartItems" : [
{
"itemName" : "Milk",
"itemPrice" : 2
}
],
"totalCost" : 2
},
{
"_id" : "003",
"buyer" : "Sheldon",
"cartItems" : [
{
"itemName" : "Butter",
"itemPrice" : 4
}
],
"totalCost" : 4
},
{
"_id" : "004",
"buyer" : "Leonard",
"cartItems" : [
{
"itemName" : "Water",
"itemPrice" : 3
}
],
"totalCost" : 3
}
Output
{
"_id" : "003_new",
"buyer" : "Sheldon",
"cartItems" : [
{
"itemName" : "Water",
"itemPrice" : 3
},
{
"itemName" : "Milk",
"itemPrice" : 2
},
{
"itemName" : "Butter",
"itemPrice" : 4
}
],
"totalCost" : 9,
"orderId" : "merged"
},
{
"_id" : "004_new",
"buyer" : "Leonard",
"cartItems" : [
{
"itemName" : "Water",
"itemPrice" : 3
}
],
"totalCost" : 3,
"orderId" : "merged"
}
Would be better if you provide example in JS.
db.orders.aggregate([
{$sort: {_id: 1, buyer: 1}},
{$unwind: '$cartItems'},
{$group: {_id: '$buyer', cartItems: {$push: '$cartItems'},
totalCost: {$sum: '$totalCost'},
id: {$last: {$concat: ["$_id", "_", "new" ]}},
buyer: {$last: '$buyer'}}},
{$addFields: {orderId: 'merged', _id: '$id'}},
{$project: {"id": 0 }}])
BTW, it's mongodb shell, but it's JS ;)
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