Unable to print by using awk command in the shell script

Question

#!/bin/bash
echo "Number of hosts entered are "$#
echo "Hostnames are "$@
for i in "$@"
do
    echo "Logging in to the host "$i
    pbsh root@$i '
    ipaddr=`ip r | awk '{print $9}'`
    if [ ipaddr = 172.*.*.* ]
    then
        echo "Script can not be run in this IP series"
        exit
    else
        cd /var/tmp ; wget http://**********
    fi'
done

After executing the above script it is throwing below error. The script is getting execute but not in the desired way.

awk: cmd. line:1: {print

awk: cmd. line:1: ^ unexpected newline or end of string

I am newbie to the scripting. Kindly correct me if anything wrong in the script.

Answer 1

In the listing which you posted, the opening single quote in the pbsh line is closed by single quote immediately followed by the awk command. You can escape the latter by prefixing it with a backslash.

If pbsh also accepts the command to be executed from stdin, an alternative would be to use a HERE document (see the bash man-page, section Here Documents ).

UPDATE: Gordon Davisson is right in his comment. \\' doesn't work either. pbsh insists on getting the command to be executed as a single argument, you could either fiddle around with the quotes, as he suggested, or put the whole input for pbsh into a separate file and use, ie,

pbsh root@$i $(<input_script.pbsh)