My python script produces a dictionary as follows:
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TL&DR
I overcomplicated the problem by using from_dict
method, while creating a dataframe from dictionary. Thanks to @Sword.
In other words, pd.DataFrame.from_dict
is only needed if you want to create a dataframe with all keys in one column, all values in another column. In all other cases, it is as simple as the approach mentioned in the accepted answer.
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{u'19:00': 2, u'12:00': 1, u'06:00': 2, u'00:00': 0, u'23:00': 2, u'05:00': 2, u'11:00': 4, u'14:00': 2, u'04:00': 0, u'09:00': 7, u'03:00': 1, u'18:00': 6, u'01:00': 0, u'21:00': 5, u'15:00': 8, u'22:00': 1, u'08:00': 5, u'16:00': 8, u'02:00': 0, u'13:00': 8, u'20:00': 5, u'07:00': 11, u'17:00': 12, u'10:00': 8}
and it also produces a variable, let's say full_name
(taken as an argument to the script) which has the value "John".
Everytime I run the script, it gives me a dictionary and name in the aforementioned format.
I want to write this into a csv file for later analysis in the following format:
FULLNAME | 00:00 | 01:00 | 02:00 | .....| 22:00 | 23:00 |
John | 0 | 0 | 0 | .....| 1 | 2 |
My code to produce that is as follows:
import collections
import pandas as pd
# ........................
# Other part of code, which produces the dictionary by name "data_dict"
# ........................
#Sorting the dictionary (And adding it to a ordereddict) in order to skip matching dictionary keys with column headers
data_dict_sorted = collections.OrderedDict(sorted(data_dict.items()))
# For the first time to produce column headers, I used .items() and rest of the following lines follows it.
# df = pd.DataFrame.from_dict(data_dict_sorted.items())
#For the second time onwards, I just need to append the values, I am using .values()
df = pd.DataFrame.from_dict(data_dict_sorted.values())
df2 = df.T # transposing because from_dict creates all keys in one column, and corresponding values in the next column.
df2.columns = df2.iloc[0]
df3 = df2[1:]
df3["FULLNAME"] = args.name #This is how we add a value, isn't it?
df3.to_csv('test.csv', mode = 'a', sep=str('\t'), encoding='utf-8', index=False)
My code is producing the following csv
00:00 | 01:00 | 02:00 | …….. | 22:00 | 23:00 | FULLNAME
0 | 0 | 0 | …….. | 1 | 2 | John
0 | 0 | 0 | …….. | 1 | 2 | FULLNAME
0 | 0 | 0 | …….. | 1 | 2 | FULLNAME
My question is two fold:
How about this?
df = pd.DataFrame(data_dict, index=[0])
df['FullName'] = 'John'
EDIT:
It is a bit difficult to understand the way you are conducting the operations but it looks like the issue is with the line df.columns = df.iloc[0]
. The above code I've mentioned will not need the assignment of column names or the transpose operation. If you are adding a dictionary at each iteration, try:
data_dict['FullName'] = 'John'
df = df.append(pd.DataFrame(data_dict, index =[0]), ignore_index = True).reset_index()
If each row might have a different name, then df['FullName'] = 'John'
will cause the entire column to equate to John. Hence as a better step, create a key called 'FullName' in your dict with the appropriate name as its value to avoid assigning a uniform value to the entire column ie
data_dict['FullName'] = 'John'
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