Capturing a process running more than 30 mins and send the report

Question

I have written a small code which is capturing the "rm" process running on the OS.. Below is the code

bash-4.1$ cat CheckRM1.py
#!/usr/bin/python
import subprocess

def Check_Ps():
    ps = subprocess.Popen(['ps', '-eo' 'pid,user,args,etime='], stdout=subprocess.PIPE)
    output = ps.communicate()[0]
    for line in output.splitlines():
        if 'rm' in line:
            pss = (line)
            print pss

Check_Ps()

When i run the code, it generate the output in the below form: this basically giving the process ID number(PID) , user name, command & at last the total time since the process running. This time basically uses the format [[dd-]hh:]mm:ss . In my case its running more than 9 mins.

bash-4.1$ ./CheckRM1.py
22908 karn     rm -i e ee q r w                  09:19

Now i'm looking to search the process which are running more 30 mins and Just print them out and send a mail. So, any idea how to capture only process running more than 30 mins, will be appreciated.

NOte: I'm using python 2.7 .

Answer 1

Question : ... how to capture only process running more than 30 mins

You are already close, split(.. the time from line by blanks, eg

import re

time_str = line.split(' ')[-1]
#  format [[dd-]hh:]mm:ss
time_items = [int(e) for e in re.split('[-:]', time_str)]

dd = 0
if len(time_items) == 2:
    hh = 0
    mm,ss = time_items
elif len(time_items) == 3:
    hh, mm, ss = time_items
else:
    dd,hh,mm,ss = time_items

print('Process is running {} Days {} Hours {} Minutes {} Seconds'.format(dd,hh,mm,ss))

time_minutes = (hh*60) + mm 
if  time_minutes >= 30:
    # do report

Tested with Python:3.4.2