I'm trying to create a client/server application where, a laptop acts like server and share its internet connection with an android phone that acts like client, I can enstablish the connection between client and server, the problem is that when the client try to write on the socket, it get stuck there. This is the android xml
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.giuseppe.client">
<uses-permission android:name="android.permission.INTERNET" >
</uses-permission>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" >
</uses-permission>
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:roundIcon="@mipmap/ic_launcher_round"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
This is the android client
package com.example.giuseppe.client;
import java.io.*;
import java.net.*;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;
import org.w3c.dom.Text;
import static java.net.InetAddress.*;
public class MainActivity extends Activity {
private Socket socket;
private static final int port=5555;
private static final String addr="192.168.1.37";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new Thread(new Client()).start();
}
public void onClick(View view){
try{
TextView tx=(TextView) findViewById(R.id.txt);
EditText et= (EditText) findViewById(R.id.et);
String str= et.getText().toString();
DataOutputStream out= new DataOutputStream(new BufferedOutputStream(socket.getOutputStream())) ;
out.writeUTF(str);
out.close();
socket.close();
}catch(UnknownHostException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}catch (Exception e){
e.printStackTrace();
}
}
class Client implements Runnable {
@Override
public void run() {
try {
TextView tx= (TextView) findViewById(R.id.txt);
tx.setText("Before connection");
InetAddress server = InetAddress.getByName(addr);
socket = new Socket("192.168.1.37", port);
tx.setText("After connection");
} catch (UnknownHostException a) {
} catch (IOException a) {
} catch (Exception a){
}
}
}
This is the server code
import java.io.*;
import java.net.*;
public class Server {
public static void main(String[] args) {
int port=5555;
byte[] buff =new byte[1024];
String str;
// TODO Auto-generated method stub
try {
ServerSocket server=new ServerSocket(port);
System.out.println("Before accept");
Socket client=server.accept();
System.out.println("After accept");
DataInputStream in=new DataInputStream(new BufferedInputStream(client.getInputStream()));
str=in.readUTF();
System.out.println("Message received");
in.close();
client.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
I suppose the problem is in the client because I also tried to use the server to send a string and while the server send it, the client doesn't receive it. Sorry for my bad english. Thanks to all
+++++EDIT+++++
I tried also OutputStream out=socket.getOutputStream(); and then out.write(str.getBytes()), but in this case it get stuck here, when I try to write in the socket, could be any android's configuration the problem?
Disclaimer: I cannot validate the correctness of your Android code so I am assuming that is fine, and only commenting on your networking code, which is the root cause of your issue.
2 main problems in your code are:
You main problem is #1 above and as soon as you resolve your #1, you will get another problem which is #2.
Your #1 problem is that you need to define some logic on how you want to consider the end of stream or input, refer below code example ( read the comments in the code ), also you don't necessarily need to use readUTF
method, instead you can use " I/O bridge classes " like InputStreamReader
which acts as a bridge between your byte stream and character stream , so you can use InputStreamReader clientSocketReader = (new InputStreamReader(clientSocket.getInputStream(), "UTF8"));
, and I cannot say why you really need DataInputStream
and can't use a InputStreamReader
but in my opinion you can go for using a bridge class.
int portNumber = 8001;
try {
ServerSocket serverSocket = new ServerSocket(portNumber);
Socket clientSocket = serverSocket.accept();
PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);
BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) { // **** this basically means that read one full line, you have to specify condition like this, so suppose you have created a telnet session with this server now keep on typing and as soon you will hit entered then while block processing will start.
System.out.println("@@@ " + inputLine);
out.println(inputLine); // *** here same input is written back to the client, so suppose you have telnet session then same input can be seen
}
} catch (IOException e) {
System.out.println(
"Exception caught when trying to listen on port " + portNumber + " or listening for a connection");
System.out.println(e.getMessage());
}
Now your #2 problem is that your server is single threaded, you need to have a multi-threaded server which basically means that you should process each client request in a new thread. Read this answer of mine which throws more light on single threaded v/s multi-threaded server. See below code example for a multi-threaded server:
import java.io.*;
import java.net.InetAddress;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import java.net.SocketTimeoutException;
import com.learn.Person;
/**
* @author himanshu.agrawal
*
*/
public class TestWebServer2 {
public static void main(String[] args) throws IOException {
startWebServer();
}
/**
* test "backlog" in ServerSocket constructor
test -- If <i>bindAddr</i> is null, it will default accepting
* connections on any/all local addresses.
* @throws IOException
*/
private static void startWebServer() throws IOException {
InetAddress address = InetAddress.getByName("localhost");
ServerSocket serverSocket = new ServerSocket(8001, 1, address);
// if set it to 1000 (1 sec.) then after 1 second porgram will exit with SocketTimeoutException because server socket will only listen for 1 second.
// 0 means infinite
serverSocket.setSoTimeout(/*1*/0000);
while(true){
/*Socket clientSocket = serverSocket.accept();*/ // a "blocking" call which waits until a connection is requested
System.out.println("1");
TestWebServer2.SocketThread socketThread = new TestWebServer2().new SocketThread();
try {
socketThread.setClientSocket(serverSocket.accept());
Thread thread = new Thread(socketThread);
thread.start();
System.out.println("2");
} catch (SocketTimeoutException socketTimeoutException) {
System.err.println(socketTimeoutException);
}
}
}
public class SocketThread implements Runnable{
Socket clientSocket;
public void setClientSocket(Socket clientSocket) throws SocketException {
this.clientSocket = clientSocket;
//this.clientSocket.setSoTimeout(2000); // this will set timeout for reading from client socket.
}
public void run(){
System.out.println("####### New client session started." + clientSocket.hashCode() + " | clientSocket.getLocalPort(): " + clientSocket.getLocalPort()
+ " | clientSocket.getPort(): " + clientSocket.getPort());
try {
listenToSocket(); // create this method and you implement what you want to do with the connection.
} catch (IOException e) {
System.err.println("#### EXCEPTION.");
e.printStackTrace();
}
}
}
}
That is an Art Producer / Consumer Problem. After the Server return from accept , the Client has an etablished Connection to the Server. While the Sever is waiting for data to read (Consumer) , The Client (Producer ) is doing nothing. The Client should write something on The Socket In order to continue.
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