Here we use a GUI to select a handset and auto update a handset_cost. The problem is how to update a tkinter textvariable in a dictionary of widgets.
I'd like to extend this simpler solution: Updating Label text after OptionMenu selection changes
You'll see from running the code below, only the final row is (incorrectly) updated when you select a handset. I've tried everything I can think of but I'm too inexperienced to see how to get the function 'displayPrice' to reference a value for each row. Please can you help, thanks.
import tkinter as tk
import datetime
class Example(tk.Frame):
def __init__(self, parent):
tk.Frame.__init__(self, parent, background="black")
root.title("Mobile Order Quote")
table = tk.Frame(self, background="black")
table.pack(side="top", fill="both", expand=True)
data = [(1, ),(2, ),(3, ),(5, )]
handset_dict1 = {'apple_iphone': 500.0, 'two_cans_plus_string': 50.0, 'samsung_galaxy': 800.0, 'none': 0.0}
table = tk.Frame(self, background="black")
table.pack(side="top", fill="both", expand=True)
self.widgets = {}
# MAKE 'big_tuple': solving the list of tuples problem - make a tuple of tuples and format too
x = list(data)
list_of_lists = [list(elem) for elem in x]
big_list = []
for i in list_of_lists:
data1=(str(i[0]))
big_list.append(data1)
big_tuple = tuple(big_list)
#global big_tuple
row = 0
for rent_id in (big_tuple):
HLabel0 = tk.Label(table, text = "ID", fg = "white", background="black")
HLabel9 = tk.Label(table, text = "Proposed_Handset", fg = "white", background="black")
HLabel10 = tk.Label(table, text = "Handset_Cost", fg = "white", background="black")
HLabel0.grid(row = 0, column = 0, padx=1, pady=1)
HLabel9.grid(row = 0, column = 9, padx=1, pady=1)
HLabel10.grid(row = 0, column = 10, padx=1, pady=1)
row += 1
handset = tk.StringVar(root) # creates tkvar for the handsets
handset.set('none')
handsetCost = tk.DoubleVar(root)
handsetCost.set(0)
def displayPrice(value):
handsetCost.set(handset_dict1[value])
self.widgets[rent_id] = {
"rent_id": tk.Label(table, text=rent_id),
"handset": tk.OptionMenu(table, handset, *handset_dict1.keys(), command=displayPrice, ),
"handset_cost": tk.Label(table, textvariable =handsetCost), }
self.widgets[rent_id]["rent_id"].grid(row=row, column=0, sticky="nsew", padx=1, pady=1)
self.widgets[rent_id]["handset"].grid(row=row, column=9, sticky="nsew", padx=1, pady=1)
self.widgets[rent_id]["handset_cost"].grid(row=row, column=10, sticky="nsew", padx=1, pady=1)
if __name__ == "__main__":
root = tk.Tk()
Example(root).pack(fill="both", expand=True)
root.mainloop()
The working solution changed considerably from the original code.
I've posted a solution in case it helps someone.
The handset and handset_cost variables were initially separated because we didn't want the string and float components together in one variable. However, the solution was to simply combine them as a single field:
HLabel9= tk.Label(table, text = "Proposed_Handset_&_cost")
"handset": ttk.Combobox(table, textvariable=handset,
values[*handset_dict1], ),
We then extracted the values, for example:
hs_buy_list = []
for rent_id in (sorted(self.widgets.keys())):
hs_buy_price = self.widgets[rent_id]['handset'] # handset and buy
new_hs_buy = hs_buy_price.get()
hs_buy_list.append(new_hs_buy)
buy_hs_int = [] # splits out the buy price of handsets
for i in hs_buy_list:
buy_hs_int.append(i.split(':')[1].rstrip('}'))
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