Using querySelectorAll on data- attribute javascript (no jQuery)

Question

I know how to select for specific classes using querySelectorAll . But How would I select for DOM object with specific data- attributes.

For example:

 <div class="person">
    <div class="detail" data-field="name">Tim</div>
    <div class="detail" data-field="age">24</div>
    <div class="detail" data-field="hair">black</div>
</div>
<div class="person">
    <div class="detail" data-field="name">Tim</div>
    <div class="detail" data-field="age">34</div>
    <div class="detail" data-field="name">red</div>
</div>
<div class="person">
    <div class="detail" data-field="name">David</div>
    <div class="detail" data-field="age">56</div>
    <div class="detail" data-field="name">brown</div>
</div>

If I want to select DOMs with a specific class eg 'detail'

 document.querySelectorAll('.detail')

My question is, How would I select for all doms with 'data-field = name?'

Answer 1

You want to use the attribute selector

 // every element with a data-field attribute var dataFieldElements = document.querySelectorAll('[data-field]'); console.log(dataFieldElements); // only those elements that have their data-field attribute equal to name var dataFieldNameElements = document.querySelectorAll('[data-field=name]'); console.log(dataFieldNameElements); 

 <div class="person"> <div class="detail" data-field="name">Tim</div> <div class="detail" data-field="age">24</div> <div class="detail" data-field="hair">black</div> </div> <div class="person"> <div class="detail" data-field="name">Tim</div> <div class="detail" data-field="age">34</div> <div class="detail" data-field="name">red</div> </div> <div class="person"> <div class="detail" data-field="name">David</div> <div class="detail" data-field="age">56</div> <div class="detail" data-field="name">brown</div> </div> 

Answer 2

Use Attribute selector

[attr=value]

Represents an element with an attribute name of attr and whose value is exactly "value".

document.querySelectorAll('.detail[data-field="name"]')