Displaying specific row from INNER JOIN - mysqli

Question

I am trying to display information about currently logged in user. The problem is information I need are in two differnet tables so I had to use INNER JOIN and I have problem to display data.

<?php 
$email = $_SESSION['email'];

$sql_address = 
"SELECT `customer`.`email`, `address`.`first_name`, `address`.`last_name` 
FROM `customer` INNER JOIN address ON `customer`.`customer_ID`=`address`.`customer_ID WHERE email =". $email; 
$result_address = $db->query($sql_address);


if(isset($_SESSION['email'])){ 
while($row = mysqli_fetch_array($result_address)){ ?>
                         <div class="col-sm-4 mb-20">
                            <div class="mb-20 mb-md-10">
                               <h3> CUSTOMER DETAILS</h3>
                               <p>Name: <?php echo $row['first_name']. " " .$row['last_name'];?><br/>
                                  Email: <?php echo $row['email'];?>
                               </p>
                            </div>
                         </div>
                         <?php }?>

At this moment I am getting this error :

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in D:\xamp\htdocs\exercises\website\shipment.php on line 149

Can you please tell me where is a problem? Also do you have any suggestion how to make it more secure? I guess putting $email into query is probably not the best idea.

Answer 1

Probably You have an error in sql statement, so $result_address is false. $email should be in single quotes, and also add close quote to the `customer_ID

Try this query

SELECT `customer`.`email`, `address`.`first_name`, `address`.`last_name` 
FROM `customer` INNER JOIN address ON `customer`.`customer_ID`=`address`.`customer_ID` WHERE email = '". $email . "'";