How to use awk counting the number of specificed digit in certain column

Question

How can I count the matched value in the certain column?

I have a file:(wm.csv)

I executed the command to get the targeted value in certain column: tail -n +497 wm.csv | awk -F"," '$2=="2" {print $3" "$4}' tail -n +497 wm.csv | awk -F"," '$2=="2" {print $3" "$4}'

then I get the following output data I want:

hit 2 hit 2 hit 2 hit 2 miss hit 2 hit 2 hit 2 hit 2 hit 2 hit 2 hit 2 incorrect 1 hit 2 hit 2 hit 2

I want to count the number of "2" in second column in order to do simple math like: total digits in column divided by total number of row. Specifically, in this case, it would looks like: 14 (fourteen "2" in second column) / 16 (total number of row)

Following is the command I tried but this does not work : tail -n +497 wm.csv | awk -F"," '$2=="2" {count=0;} { if ($4 == "2") count+=1 } {print $3,$4,$count }' tail -n +497 wm.csv | awk -F"," '$2=="2" {count=0;} { if ($4 == "2") count+=1 } {print $3,$4,$count }'

thanks

Answer 1

taking the posted data as input file

$ awk '$2==2{c++} END{print NR,c,c/NR}' file

16 14 0.875

Answer 2

awk  '($0 ~ "hit 2"){count += 1}  END{print count, FNR, count/FNR}' sample.csv
14 16 0.875

I use ~ to compare the whole line($0) matches "hit 2", if it is increase counter by 1. FNR is the file number of records which is the total line number.