How to update multiple rows in a table to MySQL

Question

First I tried to retrieve multiple rows of data from MySQL and display them in a table.

Then I tried to use foreach loop to update multiple rows into the MySQL but in vain.

If anyone has any solution would be greatly appreciated.

include('connect-db.php');

$result = mysql_query("SELECT vaccinedetail.id,vaccinedetail.vaccineid,vaccinedetail.vaccinename1,vaccinedetail.vaccinename2,vaccinedetail.vaccinename3, vaccinedetail.totalnoofinjection,vaccinedetail.nthinjection,vaccinedetail.skip 
FROM vaccinedetail 
WHERE vaccinedetail.vaccineid = '" . $_POST['vaccineid'] . "'")
or die(mysql_error());?>

<?php while($row = mysql_fetch_array( $result )){?>

<tr>
<td><input type="text" name = "id[]" value="<?php echo $row['id'] ?>"</td>

<td><input type="text" name = "vaccineid[]" value="<?php echo $row['vaccineid'] ?>"</td>
<td><input type="text" name = "vaccinename1[]" value="<?php echo $row['vaccinename1'] ?>"</td>
<td><input type="text" name = "vaccinename2[]" value="<?php echo $row['vaccinename2'] ?>"</td>
<td><input type="text" name = "vaccinename3[]" value="<?php echo $row['vaccinename3'] ?>"</td>
<td><input type="text" name = "totalnoofinjection[]" value="<?php echo $row['totalnoofinjection'] ?>"</td>
<td><input type="text" name = "nthinjection[]" value="<?php echo $row['nthinjection'] ?>"</td>
<td><input type="text" name = "skip[]" value="<?php echo $row['skip'] ?>"</td>

</tr>

<?php }?>

</table>
<input type="submit" name="submit" value="Save change">
</form>


</div>

</body>
</html>

<?php

include('connect-db.php');

if (isset($_POST["submit"])){
    foreach ($_POST['vaccineid'] as $index => $vaccineid) {
        $data1 = mysql_real_escape_string($vaccineid);
        $data2 = mysql_real_escape_string($_POST['vaccinename1'][$index]);
        $data3 = mysql_real_escape_string($_POST['vaccinename2'][$index]);
        $data4 = mysql_real_escape_string($_POST['vaccinename3'][$index]);
        $data5 = mysql_real_escape_string($_POST['totalnoofinjection'][$index]);
        $data6 = mysql_real_escape_string($_POST['nthinjection'][$index]);
        $data7 = mysql_real_escape_string($_POST['skip'][$index]);

        mysql_query("UPDATE vaccinedetail SET vaccineid ='$data1', vaccinename1 = '$data2',vaccinename2 = '$data3',vaccinename3 = '$data4',
        totalnoofinjection = '$data5', nthinjection ='$data6', skip ='$data7'") or die(mysql_error()); 
    header("Location: start.php");
    }
}
?>

<html>

<head>
  <title>Display Vaccine type</title>
</head>

<body>
  <?php
session_start();?>
    <form action="" method="POST">
      <!-- Create the table and its heading-->

      <table border='1' cellpadding='10'>
        <tr>
          <th>ID</th>
          <th>Vaccine ID</th>
          <th>疫苗名稱 (繁體)</th>
          <th>疫苗名称 (简体)</th>
          <th>Vaccine Name (Eng)</th>
          <th>Total no of injection</th>
          <th>Nth Injection</th>
          <th>Next Injection Skip</th>
          <th></th>
          <th></th>
        </tr>

Answer 1

You haven't got a WHERE clause in your update statement:

mysql_query("UPDATE vaccinedetail SET vaccineid ='$data1', vaccinename1 = '$data2',vaccinename2 = '$data3',vaccinename3 = '$data4',
        totalnoofinjection = '$data5', nthinjection ='$data6', skip ='$data7'")
or die(mysql_error());

So your update statement will update all records in the table with the values of the last update statement executed. You should pass through some kind of identifier for each record. So:

mysql_query("UPDATE vaccinedetail SET vaccineid ='$data1', vaccinename1 = '$data2',vaccinename2 = '$data3',vaccinename3 = '$data4',
        totalnoofinjection = '$data5', nthinjection ='$data6', skip ='$data7' WHERE ID = $id")

Answer 2

Well, there are a number of issues here

You're not updating at an index. This means every query will result in updating every single row. To fix this, use a WHERE clause. That will limit the number of rows.

foreach( $_POST['vaccineid'] as $index => $vaccineid ) {
    $id = mysql_real_escape_string($_POST['vaccineid'][$index]);
    /* Escape string queries */
    mysql_query(
    "UPDATE 
      vaccinedetail SET vaccineid ='$data1', 
      vaccinename1 = '$data2',
      vaccinename2 = '$data3',
      vaccinename3 = '$data4',
      totalnoofinjection = '$data5', 
      nthinjection ='$data6', 
      skip ='$data7' 
    WHERE id = $id") // <-- notice that I added a WHERE clause
        or die(mysql_error()); 
    header("Location: start.php");
}

In addition:

You're updating your data after you've already displayed your data. Move if (isset($_POST["submit"])){ to right after include('connect-db.php'); .
- You're not putting an exit statement after the call to header (this will lead to output despite the fact that you don't want it to do that.)
- You have header called after you've already sent content back to the browser ( header must be called before any content is sent in a ?> <?php section).
- You're using mysql_ library. That's deprecated. Use mysqli_ .

Answer 3

mysql_query("UPDATE vaccinedetail SET 
                            vaccineid ='".$data1."', 
                            vaccinename1 = '".$data2."',
                            vaccinename2 = '".$data3."',
                            vaccinename3 = '".$data4."',
                            totalnoofinjection = '".$data5."', 
                            nthinjection ='".$data6."', 
                            skip ='".$data7."' WHERE ID = $id;
                            ",$connectinObj) or die();

you have not add connection object.

How to update multiple rows in a table to MySQL

Question

3 answers

solution1
0 2017-06-20 14:09:16

solution2
0 ACCPTED 2017-06-20 14:10:39

solution3
0 2017-06-20 14:35:33

How to update multiple rows in a table to MySQL

Question

3 answers

solution1 0 2017-06-20 14:09:16

solution2 0 ACCPTED 2017-06-20 14:10:39

solution3 0 2017-06-20 14:35:33

solution1
0 2017-06-20 14:09:16

solution2
0 ACCPTED 2017-06-20 14:10:39

solution3
0 2017-06-20 14:35:33