how can i write as one query to get count in mysql

Question

I want to get the today count of users and yesterday's users count for that i want to write only one query how can i do that..?

these are my queries I want only one query:

SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,1 as todayCount

SELECT COUNT(*) FROM visitors group by visited_date ORDER by visited_date DESC limit 1,0 as yesterdayCount

My expected results or only 2 columns

todayCount yesterdayCount
     2          4

Answer 1

This should do the trick:

SELECT COUNT(CASE 
                WHEN visited_date = CURDATE() THEN 1 
             END) AS todayCount ,
       COUNT(CASE 
                WHEN visited_date = CURDATE() - INTERVAL 1 DAY THEN 1 
             END) AS yesterdayCount 
FROM visitors  
WHERE visited_date IN (CURDATE(), CURDATE() - INTERVAL 1 DAY)
GROUP BY visited_date
ORDER by visited_date 

Answer 2

If you know the current and previous date, then you can do:

SELECT SUM(visited_date = CURDATE()) as today,
       SUM(visited_date = CURDATE() - interval 1 day) as yesterday
FROM visitors
WHERE visited_date >= CURDATE() - interval 1 day;

If you don't know the two days, then you can do something similar, getting the latest date in the data:

SELECT SUM(v.visited_date = m.max_vd) as today,
       SUM(v.visited_date < m.max_vd) as yesterday
FROM visitors v CROSS JOIN
     (SELECT MAX(v2.visited_date) as max_vd FROM visitors v2) as m
WHERE v.visited_date >= m.max_vd - interval 1 day

Answer 3

Just try this simple query

select visited_date as date, COUNT(*) as count from `visitors` 
group by `visited_date` order by `visited_date` asc

It will produce output as

It will work for you.

Answer 4

Try this: $sqlToday = "Select COUNT(*) FROM menjava WHERE DATE(date_submitted)=CURRENT_DATE()";

$sqlYesterday = "Select COUNT(*) FROM menjava WHERE DATE(dc_created) = CURDATE() - INTERVAL 1 DAY";