How to copy the hidden field value and pass it on another page using jquery in CodeIgniter?
Question
I am new with CodeIgniter and I want to pass hidden field value to another page using jQuery in CodeIgniter. Can I do this using jQuery?
<input type="hidden" name="grdtot" class="grdtot" />
this hidden field on cart.php page
<label id="grdtot_c" name="grdtot_c" class="grdtot_c"></label>
I want to fetch this hidden field value on checkout.php page. How I can do this using jQuery?
2 answers
solution1
2 ACCPTED 2017-07-08 07:25:35
You can do this another way using localstorage to getting value from another page
Just write like this on page one.
localStorage.setItem('Gridtotal', $('.grdtot').val());
And get value from another page.
var grdTotal= localStorage.getItem('Gridtotal');
$('#grdtot_c').val(grdTotal);
solution2
0 2017-07-08 16:02:31
Suppose You have form given below:
<body>
<div>Upload data to the server without page Refresh</div>
<input type="hidden" name="hidden_name" id="hidden_name">
<input type="text" name="name" id="name">
<input type="text" name="email" id="email">
<input type="text" name="website" id="website">
<input type="submit" name="submit" id="save" value="Submit">
<div id="display"></div>
</body>
And Now Your Script to send data to Your Controller . You must have to use ajax to send data to the controller in CodeIgniter, And It will make your work easy.
<script>
$(document).ready(function(){
$('#save').click(function(){
var hidden_name = $('#hidden_name').val();
var name = $('#name').val();
var email = $('#email').val();
var website = $('#website').val();
$.ajax({
type:'POST',
url:'<?php echo base_url();?>index.php/controller_name/function_name',
async:false,
data:{
"done":1,
"hidden_name":hidden_name,
"name":name,
"email":email,
"website":website
},
success:function(data){
$('#display').html(data);
}
});
});
});
</script>
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