In java generic programming, is the Object class upper bound or lower bound of the parameter type without wildcard?

Question

when answering the question Creating generic array in Java via unchecked type-cast , newacct said

(The lower bound of Bar is Object in this question. In a case where the lower bound of Bar is something else, replace all occurrences of Object in this discussion with whatever that bound is.)

Here is newacct's code:

class Foo<Bar> {
    Bar[] bars = (Bar[])new Object[5];
    public Bar get(int i) {
        return bars[i];
    }
    public void set(int i, Bar x) {
        bars[i] = x;
    }
    public Bar[] getArray() {
        return bars;
    }
}

I wonder whether Object is the upper bound or lower bound of Bar . I think that Foo<Bar> is short for Foo<Bar extends Object> , so Object should be the upper bound of Bar , am I wrong?

Answer 1

Given a type variable declaration <T extends TypeName> , TypeName is the upper bound of T . Technically, I think it's just the bound , since the upper/lower distinction is only made for wildcards . Additionally, if no bound is specified, then Object is assumed , so you're right that Object is the bound of Bar in the example.

I think newacct just misspoke when they wrote the answer and meant to say 'upper bound' instead of 'lower bound'.

Edit : Also, when talking about the particular construct in the referenced Q&A, it's useful to point out that the erasure of a type variable is the erasure of its left-most bound which is the importance of replacing the element type used for the array creation with the type used in the bound. For example, given a complex type variable declaration <T extends Comparable<T> & Serializable> , the erasure of T would be Comparable , so you would use Comparable[] or Comparable<?>[] .

Answer 2

You can define the lower bound as follows in generics as well.

class Foo<T extends Bar> {
T[] bars = (T[])new Object[5];
public T get(int i) {
    return bars[i];
}
public void set(int i, Bar x) {
    bars[i] = x;
}
public T[] getArray() {
    return bars;
}

}

So you can create a Foo object with any class that extends Bar.

No, you cannot use Object typed instances and lower bound is Bar and upper bound is any class that extends Bar class .