Concatenating strings with spaces using Python

Question

When I run this code it behaves like expected:

x = int(input("Put number: "))
result_figure =[]
xtempleft = x-1
xtempright = 0
space = " "
sl = "/"
bsl  = "\\"
#Q1
for i in range(x):
    if xtempleft > 0:
        q1= space * xtempleft + sl
        xtempleft -= 1
        print(q1)

    else:
        q1 = sl
        print(q1)
#Q2
for i in range(x):
    if xtempright == 0:
        xtempright += 1
        q2= bsl 
        print(q2)
    else:
        q2 = space * xtempright + bsl
        xtempright += 1
        print(q2)

I get this:

    /
   /
  /
 /
/
\
 \
  \
   \
    \

The problem is that when I try to do some modification:

for i in range(x):
    result =""
    if xtempleft > 0:
        q1= space * xtempleft + sl
        xtempleft -= 1
        result += q1     
    else:
        q1 = sl
        result += q1
#Q2
    if xtempright == 0:
        xtempright += 1
        q2= bsl 
        result += q2
    else:
        q2 = space * xtempright + bsl
        xtempright += 1
        result += q2  
    print(result)

to print what I need in the same line i get it like spaces from Q2 disappeared somewhere and didn't concatenate.

    /\
   / \
  /  \
 /   \
/    \

Anyone could help me with this? I have tried in many ways and can't get it.

Answer 1

In modification you omitted the for loop.

In your initial code there are two for loops and in your modification you omitted the second for loop.

Answer 2

If this is your expected output,

    /\
   /  \
  /    \
 /      \
/        \

Modify #Q2 to :

if xtempright == 0:
        xtempright += 1
        q2= bsl 
        result += q2
    else:
        q2 = space * (xtempright+1) + bsl
        xtempright += 2
        result += q2

Answer 3

As the / goes one position left on each line, you need one additional space before the \\ . It is enough to write in Q2:

    q2 = space * 2 * xtempright + bsl