I try to pass Integer::parseInt as an argument to another function.
But since Integer::parseInt can take either (String) or (String, int) as input, the method can't be resolved.
public static void main(String[] args) {
Hello h = new Hello();
h.withinRange(Integer::parseInt);
}
public void withinRange(Function<Integer, String> function) {
}
}
I am not sure whether this is doable or not.
您需要将其声明为public void withinRange(Function< String,Integer> function)
或public void withinRange(ToIntFunction< String> function)
(无论public void withinRange(ToIntFunction< String> function)
都更合适)。
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