Matching pattern over multiple lines in Python

Question

I am new to Python regex. I trying to get below lst from the output.

output="""
IP = 10.10.10.1
BGP version 4, remote router ID 0.0.0.0
State = Established
IP = 10.10.10.2
BGP version 4, remote router ID 0.0.0.0
State = Active
IP = 10.10.10.3
BGP version 4, remote router ID 0.0.0.0
State = Active
IP = 10.10.10.4
BGP version 4, remote router ID 0.0.0.0
State = Established
"""

I am trying with below regex but no luck. Can someone please help me.

lst = re.findall(r'IP = (\S+)\n\nState = (\S+)',output, re.M)

lst should be filled with

[('10.10.10.1', 'Established'), ('10.10.10.2', 'Active'), ('10.10.10.3', 'Active'), ('10.10.10.4', 'Established')]

Answer 1

Try this:

In [101]: pat = r'IP\s*\=\s*([^\n\r]*)[\r\n][^\=]*?State\s*\=\s*([^\n\r]*)'

In [102]: re.findall(pat, output, flags=re.M & re.S)
Out[102]:
[('10.10.10.1', 'Established'),
 ('10.10.10.2', 'Active'),
 ('10.10.10.3', 'Active'),
 ('10.10.10.4', 'Established')]

NOTE: please pay attention at @WiktorStribiżew's RegEx , which is much more elegant:

re.findall(r'(?sm)^IP = (\S+).*?^State = (\S+)',output)