I have a folder of a few hundred Excel files all organized identically with nine sheets in each workbook. I am running the following code to iterate over the files and create one dataframe for each worksheet across all workbooks (so dataframe "sheet_a_df" will be sheet "a" from every workbook concatenated into a single dataframe).
sheet_a_df = pd.DataFrame()
for file in glob.glob('C:\\Users\*.xlsx'):
df = pd.read_excel(file,sheetname='a')
sheet_1_df = sheet_1_df.append(df,ignore_index=True).dropna()
sheet_b_df = pd.DataFrame()
for file in glob.glob('C:\\Users\\*.xlsx'):
df = pd.read_excel(file,sheetname='b')
sheet_b_df = sheet_b_df.append(df,ignore_index=True).dropna()
# And so on for all nine sheet names...
However, this requires copy and pasting the code nine times (once for each sheet).
Is there a more appropriate way to do this?
Reviewing this question , I understand dictionaries are the way to go for creating multiple dataframes in a for loop. I am also trying to name each df according to the worksheet's name . I created a list of my sheet names and tried the following code, but am getting a KeyError that simply returns the first sheet's name.
sheet_names = ['a',
'b',
'c',
...,]
df_dict = {}
for file in glob.glob('C:\\Users\*.xlsx'):
for sheet in sheet_names:
df = pd.read_excel(file,sheetname=sheet)
df_dict[sheet] = df_dict[sheet].append(df)
Is there a way to fix the above code to create all nine dfs while naming them according to the sheets they come from?
You are trying to append a dataframe to a non-existent dictionary item. You should first check if the key exists:
for file in glob.glob('C:\\Users\*.xlsx'):
for sheet in sheet_names:
df = pd.read_excel(file,sheetname=sheet)
if sheet in df_dict:
df_dict[sheet] = df_dict[sheet].append(df)
else:
df_dict[sheet] = df
You can take advantage of the fact that if you pass a list
of sheet names to the sheetname
parameter of the pd.read_excel
function, it will return a dictionary of dataframes where the keys are the sheet names and the values are the dataframes corresponding to those sheet names. As a result, the following should get you a dictionary of concatenated dataframes: all "a" dataframes together, all "b" dataframes together, so on.
sheet_names = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i']
data = {}
for fn in glob.glob('C:\\Users\*.xlsx'):
dfs = pd.read_excel(fn, sheetname=sheet_names)
for k in dfs:
data.setdefault(k, pd.DataFrame())
data[k] = pd.concat([data[k], dfs[k]])
Now data
should be a dictionary of dataframes with keys containing elements from sheet_names
. Its values are the concatenated dataframes of corresponding sheet names from your files.
I hope this helps.
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