简体   繁体   中英

Django - printing multiple passed lists from views.py

I have 4 lists with the same length and would like to pass all of them to the html page.

views.py

return render(request, 'result.html', {'listA':listA, 'listB':listB,  'listC':listC, 'listD':listD})

And here is the code when I tried with Flask.

app.py

return render_template('result.html', listA = listA, listB = listB, listC = listC, listD = listD)

Below is the code in the template file; with Flask, it prints out the table without any problems, but it doesn't seem to work with Django. How should I fix my code?

result.html

{% for i in listA %}
<tr>
<th> {{ listA[loop.index] }} </th>
<td> {{ listB[loop.index] }} </td>
<td> {{ listC[loop.index] }} </td>
<td> {{ listD[loop.index] }} </td>
</tr>
{% endfor %}

You should use a custom templatetag for implementing lookup, because django does not provide one for you. and then use django template engine for loop for getting forloop.counter0

First create templatetags directory with __init__.py inside your app folder. Lets assume your app is called polls folder structure will look like this:

polls/
    __init__.py
    models.py
    templatetags/
        __init__.py
        lookup.py
    views.py

After write lookup code which goes inside lookup.py :

from django import template

register = template.Library()

@register.filter
def lookup(d, key):
    return d[key]

And finlly use it in template file:

{% load lookup %}
...
{% for i in listA %}
    <tr>
        <th> {{ listA|lookup:forloop.counter0 }} </th>
        <td> {{ listB|lookup:forloop.counter0 }}</td>
        <td> {{ listC|lookup:forloop.counter0 }}</td>
        <td> {{ listD|lookup:forloop.counter0 }}</td>
    </tr>
{%  endfor %}
...

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM