get all values from child node Xml with Java

Question

I'm trying to parse an XML file to make out of it excel file by using Java
and I can't understand how to retrieve all child nodes like these names ?

   <Products>
        <companies>
            <name>Al Rawabi</name>
            <name>Al Rifai</name>
            <name>Colgate-Palmolive</name>
            <name>Danone (Nutrition)</name>
            <name>Henkel</name>
        </companies>
    <Products>

I tried to make it this way, but as a result I'm getting an empty lists of names.

    NodeList ListOfProducts = xmlDoc.getElementsByTagName("Products"); //first we need to find total number of Products blocks
    int totalProducts = ListOfProducts.getLength();
        System.out.println("Total no of Products : " + totalProducts);
    for(int s = 0; s < ListOfProducts.getLength(); s++)
    {
        Node ProductsNode = listOfProducts.item(s);
        System.out.println("Products number : " + s);
        if (ProductsNode.getNodeType() == Node.ELEMENT_NODE)
        {
            Element ProductElement = (Element) ProductsNode;
            NodeList CompanyList = ProductElement.getElementsByTagName("companies"); // find node companies
            System.out.println("companies number : " + CompanyList.getLength());
            for(int cl = 0; cl < CompanyList.getLength(); cl++) {
                NodeList CompanyNameList = CompanyList.item(cl).getChildNodes();
                for (int j = 0; j < CompanyNameList.getLength(); j++) {
                    Node childNode = CompanyNameList.item(j);
                    if ("name".equals(childNode.getNodeName())) {
                        for (int nl = 0; nl < CompanyNameList.getLength(); nl++) {
                            Element CompanyNameElement = (Element) CompanyNameList.item(nl);
                            NodeList textFNList = CompanyNameElement.getChildNodes();
                            System.out.println("Company: " + nl + " :" + (textFNList.item(0)).getNodeValue().trim());
                            CompaniesNames.add((textFNList.item(0)).getNodeValue().trim());
                        }
                    }
                }
            }
        }// end of if clause
    }// end of for loop with s var

Answer 1

//load the xml file
function loadDoc(){
    //create the xml request
    var xhttp = new XMLHttpRequest();
    xhttp.onreadystatechange = function() {
        if (this.readyState == 4 && this.status == 200) {
           myFunction(this);
        }
    };
    //open and send the request
    xhttp.open("GET", "filename.xml", true);
    xhttp.send();
}

//print the xml data in html
function myFunction(xml) {
    var i;
    var xmlDoc = xml.responseXML; //xml file loaded
    var x = xmlDoc.getElementsByTagName("companies");
    //loop through xml element
    for (i = 0; i < x.length; i++) {
        x[i].getElementsByTagName("name")[0].childNodes[0].nodeValue;
    }
}

This is the JavaScript version of doing you want to do. Hope you can use some of it in Java!

Answer 2

Below is how you can do it in XPath and VTD-XML. Beware that I am the author of VTD-XML so my pov may be biased.

import com.ximpleware.*;

public class extractName{
   public static void main(String s[]) throws VTDException{

          VTDGen vg = new VTDGen();
          if (!vg.parseFile("input.xml",false))
             return false;
          VTDNav vn = vg.getNav();
          AutoPilot ap =new AutoPilot(vn);
          ap.selectXPath("/Products/companies/names/text()");
          int i=0;
          while((i=ap.evalXPath())!=-1){
              System.out.println(" name is ===>"+vn.toString(i));
          }

   }
}