def isprimelike(n):
for a in range(2,n-1):
if pow(a,n,n) == a%n:
return True
else:
return False
When I check n
for a given value it just check 2
, then decides if it is true or false and doesn't check the rest of the range. Not sure how to make it check the rest of the range.
That's because you're using a return
inside the if-else block. You might want to change the return
statement by a print
one indicating if it is a prime number or not.
If you want it to return True
if all are prime-like or False
if at least one is not, then do the following:
def isprimelike(n):
for a in range(2,n-1):
if pow(a,n,n) != a%n:
print('One element is false')
return False
return True
The print statement is just to show something, but it's not relevant.
I would try making a list and allow your for loop to append the results of the range into the list then return the list as a whole so you can have access to all the results.
edit: Complely missed the point of your question. Here's the edit.
import sys
def isprimelike(n):
resultlist = []
for a in range(2,int(n)-1):
if pow(a,int(n),int(n)) == a%int(n):
result.append(True)
else:
result.append(False)
return resultlist
n = sys.argv[1]
resultlist = isprimelike(n)
if True in resultlist:
if False in resultlist:
print('List contains both True and False')
sys.exit(1)
else:
print('List is all True')
sys.exit(1)
if False in resultlist:
if True in resultlist:
print('List contains both True and False')
else:
print('List is all False')
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