Javascript variable not working in php echo

Question

My code :

<?php echo ' <script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques".p);? >

The value of p is displayed as 0.

Answer 1

You need to close your php tag properly as well as the <script> tag like so:

<?php echo '<script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques" +p);</script>'; ?>

Also, change the . to a + as you are concatenating in javascript not PHP

Answer 2

正确答案是：

<?php echo '<script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques" + p)'; ?>

Answer 3

单引号中的字符串将被转义，请改用引号。

<?php echo "<script>var p=0;for(var i=0;i<=5;i++){p++;}alert('ques' +p);</script>"; ?>

Answer 4

The mistakes in your code are,

1. Close your php tag properly - ?> instead of ? > ?> instead of ? >
2. Close the script tag in the end - </script>
3. Close the single quote you started with echo

The correct code would be

<?php echo '<script>var p=0;for(var i=0;i<=5;i++){ p++; } alert("ques" + p); </script>'; ?>