In javascript, I have an array of items like so:
[
'title',
'firstname',
'company',
'[m]usr_phone'
'[m]usr_city'
]
I would like to sort this using a custom array sort function so that all the non [m] items are sorted at the top, and all the [m] items are sorted and pushed to the bottom (after all the non [m] items)
To achieve this I tried a sort function like this:
function(a, b) {
if (!a.indexOf('[m]') && b.indexOf('[m]') === 0
|| a.indexOf('[m]') && b.indexOf('[m]')) {
return -1;
}
if (a.indexOf('[m]') === 0 && !b.indexOf('[m]')) {
return 1;
}
return 0;
}
But couldn't get it to work properly. I would like the output to be:
[
'company',
'firstname',
'title',
'[m]usr_city'
'[m]usr_phone'
]
Thanks for your help!
You could check the prefix and sort later by String#localeCompare
.
var array = ['title', 'firstname', 'company', '[m]usr_phone', '[m]usr_city']; array.sort(function (a, b) { return (a.slice(0, 3) === '[m]') - (b.slice(0, 3) === '[m]') || a.localeCompare(b); }); console.log(array);
You want to compare items in the same “class” (ie either starting with [m]
or not) the same way, so use a.startsWith("[m]") == b.startsWith("[m]")
to do this, and then use String#localeCompare
.
console.log([ "company", "firstname", "title", "[m]usr_phone", "[m]usr_city" ].sort((a, b) => { if (a.startsWith("[m]") == b.startsWith("[m]")) { return a.localeCompare(b); } else { return (a.startsWith("[m]") ? 1 : -1); } }));
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