I have the registered Comment
model which has a User
reference, like this:
public function user() {
return $this->belongsTo('App\User');
}
This function returns an instance of a User
, and that's correct, but I don't know how to register the User
column the get que user
property using Backpack. Instead, I'm get a JSON representation of my model:
So, how do I get a specific field from my relationship function ?
Sounds like the select column is a perfect match for you. Just use it in your EntityCrudController's setup()
method, like so:
$this->crud->addColumn([
// 1-n relationship
'label' => "User", // Table column heading
'type' => "select",
'name' => 'user_id', // the column that contains the ID of that connected entity;
'entity' => 'user', // the method that defines the relationship in your Model
'attribute' => "user", // foreign key attribute that is shown to user
'model' => "App\Models\User", // foreign key model
]);
The "attribute" tells CRUD what to show in the table cell (the name, the id, etc).
If you do:
$user = $comment->user->user;
You'll get 'test'; (from your example)
It may seem confusing because your User model has a user attribute. Maybe you can call it 'name' instead of 'user'. That way you'll call it:
$username = $comment->user->name;
Remember to check if the relationship exists before calling a property on the related model.
if(!is_null($comment->user)) {
$username = $comment->user->user;
}
Or:
$username = !is_null($comment->user) ? $comment->user->user : 'No user';
If you need to get some field from deeper relation, you can use closure column type:
$this->crud->addColumn([
'label' => trans('backend.column_names.agency_linked_service'),
'name' => 'agency_service_id',
'type' => 'closure',
'function' => function (AgencyLinkedServices $entry) {
return $entry->agencyService->agencyCategory->title;
}
]);
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