So I have a dictionary;
dictionary = {"one": ["two"], "two": ["three"], "three": [None]}
How can I recursively go through in a function to find one if i am given three? example: does one end up as three? Yes because one --> two --> three and the same back down. three --> two --> one
So far I have tried to use a list comprehension on the dictionary;
def function(start, end, dict_to_check):
if dict_to_check[end] == start:
return True
else:
var = {key: value for key, value in dict_to_check.items() if value == start}
return var
but this does not use recursion and I have no idea how to go about
You can try this:
start = "one"
end = "three"
dictionary = {"one": ["two"], "two": ["three"], "three": [None]}
def check(s):
if not dictionary[s][0]:
return "Not found"
if dictionary[s][0] == end:
return "found"
else:
return check(dictionary[s][0])
print(check(start))
Output:
found
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