I have a character column with a different amount of values per row. This is just a small example:
GoodForMeal %>% head(5)
# A tibble: 5 x 1
GoodForMeal
<chr>
1 dessert': False, 'latenight': False, 'lunch': True, 'dinner': True
2 dessert': False, 'latenight': False, 'lunch': True, 'dinner': True
3 <NA>
4 dessert': False, 'latenight': False, 'lunch': True, 'dinner': True
5 dessert': False, 'latenight': False, 'lunch': True, 'dinner': True
Here is a dput()
of the first row of the column:
structure(list(GoodForMeal = "dessert': False, 'latenight': False, 'lunch': True, 'dinner': True, 'breakfast': False, 'brunch': False}"), .Names = "GoodForMeal", row.names = c(NA,
-1L), class = c("tbl_df", "tbl", "data.frame"))
I want to assign the values before the colon as column names and the values after the colon as the values of the respective column.
Example:
desert latenight lunch diner
1 False False True True
2 False False True True
3 NA NA NA NA
4 False False True True
5 False False True True
I tried it with the tidyr
packadge and the separate
and the spread
function:
separate(GoodForMeal, c("key", "value"), sep = ":", extra = "merge") %>% spread(key, value)
The problem is the r is not splitting all the values before the colon but just the first value.
So the result looks like this:
GoodForMeal %>% str()
Classes ‘tbl_df’, ‘tbl’ and 'data.frame': 4464 obs. of 2 variables:
$ dessert': chr " False, 'latenight': False, 'lunch': True, 'dinner': False, 'breakfast': False, 'brunch': False}" " False, 'latenight': False, 'lunch': True, 'dinner': True, 'breakfast': False, 'brunch': False}" " False, 'latenight': False, 'lunch': False, 'dinner': False, 'breakfast': False, 'brunch': False}" " False, 'latenight': False, 'lunch': True, 'dinner': True, 'breakfast': False, 'brunch': False}" ...
$ <NA> : chr NA NA NA NA ...
Any Idea how to split the values so that it´s looking like in the example? THX
Working with the test data you've provided, I would use mutate
first to rid the column of characters such '
and :
, along with the meal time keywords. This allows you to split on the comma that separates the various meal times. The following is an illustration:
df <- structure(list(GoodForMeal = "dessert': False, 'latenight': False, 'lunch': True, 'dinner': True, 'breakfast': False, 'brunch': False}"),
.Names = "GoodForMeal", row.names = c(NA, -1L),
class = c("tbl_df", "tbl", "data.frame"))
df %>%
mutate(GoodForMeal = trimws(gsub("[':]|dessert|lunch|dinner|latenight|brunch",
"",
GoodForMeal))) %>%
separate(GoodForMeal,
c("dessert", "latenight", "lunch", "dinner"),
", ",
extra="drop")
It should yield:
# A tibble: 1 x 4
# dessert latenight lunch dinner
# * <chr> <chr> <chr> <chr>
# False False True True
I hope this proves useful.
This is not an elegant solution (and long) but seems to work. I did change the data to make it more general. Hope this can be a good start.
# i made some changes in the data; remove lunch entry in the 4th element and remove dessert in the 1st
sampleData <- c("'dessert': False, 'latenight': False, 'lunch': True, 'dinner': True",
"'dessert': False, 'latenight': False, 'lunch': True, 'dinner': True",
NA,
"'dessert': False, 'latenight': False, 'dinner': True",
"'latenight': False, 'lunch': True, 'dinner': True")
# [1] "'dessert': False, 'latenight': False, 'lunch': True, 'dinner': True"
# [2] "'dessert': False, 'latenight': False, 'lunch': True, 'dinner': True"
# [3] NA
# [4] "'dessert': False, 'latenight': False, 'dinner': True"
# [5] "'latenight': False, 'lunch': True, 'dinner': True"
# not sure if this is necessary, but jsut to clean the data
sampleData <- gsub(x = sampleData, pattern = "'| ", replacement = "")
# i'm a data.table user, so i'll jsut use tstrsplit
# split the pairs within each elements first
x <- data.table::tstrsplit(sampleData, ",")
# split the header and the entry
test <- lapply(x, function(x) data.table::tstrsplit(x, ":", fixed = TRUE))
# get the headers
indexHeader <- do.call("rbind", lapply(test, function(x) x[[1]]))
# get the entries
indexValue <- do.call("rbind",
lapply(test, function(x){if(length(x) > 1){ return(x[[2]])}else{ return(x[[1]])} }))
# get unique headers
colNames <- unique(as.vector(indexHeader))
colNames <- colNames[!is.na(colNames)]
# determine the order of the entries using the header matrix
indexUse <- apply(indexHeader, 2, function(x) match(colNames, x))
# index the entry matrix using the above matching
resA <- mapply(FUN = function(x,y) x[y],
x = as.data.frame(indexValue),
y = as.data.frame(indexUse))
# convert to data frame
final <- as.data.frame(t(resA))
# rename columns
colnames(final) <- colNames
# should give something like this
final
# dessert latenight lunch dinner
# False False True True
# False False True True
# <NA> <NA> <NA> <NA>
# False False <NA> True
# <NA> False True True
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