this is quite the nooby questions, it's just that I havn't been doing this for a long time and would need some help.
So here is the problem. I have this debug info on my list "lstfriendlist":
I simply put up a breakpoint in my activity, then clicked on my list and saw, that all my "friends" are brought to me on this list under "friendUsername".
I was able to retrieve a certain username via:
string temp = lstfriendList[11].friendUsername.ToString();
This returns "torben" on my string "temp".
Now I just forgot how to use the foreach loop to retrieve all objects in order from my list and then write them down. I'm sorry to bother you with this, but I simply forgot :(
I hope you can help me. Thank you :)
You already have declared a variable of the type "Friend" in the foreach loop's head. Now you can access the properties of the current object by typing
foreach (Friend f in lstfriendList)
{
string temp = f.friendUsername;
}
To complete Sebastian Hofmann answer, you can use .OrderBy or .OrderByDescending to order on name or username
foreach (Friend f in lstfriendList.OrderBy(list => list.friendUsername))
{
string temp = f.friendUsername;
}
Will return user name from a to z
foreach (Friend f in lstfriendList.OrderByDescending(list => list.friendUsername))
{
string temp = f.friendUsername;
}
Will return username z to a
I think there is no way to stuck there, since you are now having the Friend
object( f
) with you inside the loop, just place a .
after f
and see what intellisense suggests, Anyway It is pretty good if you modify the class like the following, with override ToString() :
class Friend
{
public string friendUsername { get; set; }
public int friendId { get; set; }
// Add rest of properties here
public override string ToString()
{
return "ID :" + friendId + "\n Friend Name: " + friendUsername;
// Append rest of properties here
}
}
And then use like this:
foreach (Friend f in lstfriendList)
{
string friendDetails = f.ToString();
Console.WriteLine(friendDetails);
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.