NumberFormatException while converting a string to an integer value in java

Question

When I'm trying to parse the input1 string to an integer value it's rising a NumberFormatException.I've tried replacing the spaces if any in the string but it didn't work for me.

int number = 0;
 String input1 = "12345354987"; 
 try{
   ip = Integer.parseInt(input1);

  }catch(NumberFormatException e){
        System.out.println("not a number");
    }

Answer 1

12345354987 > 2,147,483,64

Integer max range is 2,147,483,647 and you are crossing it. You may use Long or BigDecimal for big numbers.

Answer 2

Its because the Number in String is out of Integer range, If you really need this than use BigInteger for large values like this :

 String input1 = "12345354"; 
         BigInteger ib =new BigInteger(input1);
         System.out.println(ib);

or For small values that can fit in Long range you can use :

String input1 = "1234535455"; 
           Long ip = Long.parseLong(input1);
           System.out.println(ip);

Answer 3

您的数字大于整数最大值，请使用长然后尝试解析。