简体   繁体   中英

Excel Conditional formatting highlight the bottom 3 values in colum C for each unique value in column A

This is just an example, but I have 3 columns. Name, Level and Impact. What I am trying to do is create a conditional formatting so the bottom 3 values in the impact column are highlighted for each unique value of Name and level combined (so =Name&Level would be my unique identifier). Is this even possible? below is a sliver of sample data to paint a clearer picture.

So one example would be these rows being highlighted for Eric2

Name    Level   Impact
Jack    1   -0.17 
Barry   1   -0.16 
Janice  2   -0.10 
Barry   3   -0.08 
Janice  4   -0.07 
Eric    4   -0.07 
Janice  1   -0.05
Eric    2   -0.04 <--Highlight
Jack    2   -0.04
Lisa    3   -0.04
Lisa    3   -0.04
Lisa    4   -0.03
Barry   2   -0.03
Jack    4   -0.03
Janice  1   -0.03
Janice  1   -0.03
Eric    2   -0.02 <--Highlight
Barry   2   -0.02
Eric    4   -0.02
Eric    4   -0.02
Barry   3   -0.02
Eric    4   -0.02
Janice  2   -0.02
Eric    1   -0.02
Eric    4   -0.02
Janice  3   -0.02
Eric    2   -0.02 <--Highlight
Eric    2   -0.02 <--Highlight

Thanks!

=IFERROR(C2<=SMALL(IF(ROW($C$2:$C$33)-1=MATCH(IF(A2&B2=$A$2:$A$33&$B$2:$B$33,$C$2:$C$33),IF(A2&B2=$A$2:$A$33&$B$2:$B$33,$C$2:$C$33),0),IF(A2&B2=$A$2:$A$33&$B$2:$B$33,$C$2:$C$33)),3),TRUE())

为我工作。

At risk of over-simplifying, if OP is confident that all the impact values are distinct values (at least within a particular name and level) then it would be enough just to count how many values there are less than the current one.

=COUNTIFS($A$2:$A$10,$A2,$B$2:$B$10,$B2,$C$2:$C$10, "<"&$C2)<3

On the other hand if there is a possibility of ties and OP wanted to highlight all rows corresponding to bottom 3 distinct values, could use this

=SUM(--(FREQUENCY(IF(($A$2:$A$10=$A2)*($B$2:$B$10=$B2)*($C$2:$C$10<$C2),$C$2:$C$10),$C$2:$C$10)>0))<3

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM