Linux find and replace: how to escape single quotes in strings?

Question

Total newbee on this, so here's what is not working:

find . -type f -exec sed -i 's/\$_SESSION['valOne']"/\$valTwo,"/g' {} +

While it should replace recursively, in all the directories it is going through:

$_SESSION['valOne'] into just: $valTwo

I've done this many times, but it seems the quotes are too confusing for me. Any help here is highly appreciated.

Answer 1

如果我了解您正在尝试做什么（字面替换），那么您需要单引号字符串，以便 shell 不会尝试解释其内容，然后对字符串中的每个单引号使用'\\''并转义任何BRE 元字符（即[和]在您的情况下）：

find . -type f -exec sed -i 's/$_SESSION\['\''valOne'\''\]"/$valTwo,"/g' {} +

Answer 2

Please try as follows. Change the ' -> " and escape with the backslash.

Example:

 find . -type f -exec sed -i "s/\$_SESSION\['valOne'\]/\$valTwo/g" {} +