Printing specific values from list in Python 3

Question

I was wondering if there is a different and shorter way to print specific values in a list without having to repeat print(num[x],num[x],num[x]) many times

num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]

print(num[5])
print(num[5], num[12])

Answer 1

Just loop like this:

for i in [5, 12]:
   print(num[i], end=' ')

Answer 2

You could use operator.itemgetter :

>>> from operator import itemgetter
>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> itemgetter(5, 12)(num)
('5', 'c')

Answer 3

You could use list comprehension:

>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> print( [num[x] for x in (5, 12)] )
['5', 'c']

Answer 4

You can simply define a function.

def getVal(List, *index):
    for x in index:
        print(List[x], end=" ")

 num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
 getVal(num, 1, 5, 3)

 # 1 5 3

Answer 5

You can just map() what you want:

>>> num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]
>>> list(map(lambda x: num[x], [5, 12]))
['5', 'c']

Answer 6

You need a function :

num=["0","1","2","3","4","5","6","7","8","9","a","b","c","d","e"]

def index_no(first,second):
    try:
        return (num[first],num[second])
    except IndexError:
        pass

print(index_no(5,12))

output:

('5', 'c')