My first array is:
arr1 = [1, 2, 3, 4, 5]
My second array is:
arr2 = [2, 3, 4]
My third array is:
arr3 = ["2a", "3a", "4a"]
arr2 and arr3 are related by index values, ie, arr2[0] relates to arr3[0], same for [1] and [2].
I have been able to compare arr2 against arr1 and add placeholder values so my placeholder array for them is
arr1to2 = ["No match", 2, 3, 4, "No Match"]
Now I need to compare arr3 against arr2 to arr1 (alternatively arr1to2), so my output should be
array_final = ["No match", 2a, 3a, 4a, "No match"]
I need to have the relationship maintained between index values of array_final and arr1to2 as well. [1] relates [1], [2] to [2], [3] to [3].
You can do it this way:
let arr1 = [1, 2, 3, 4, 5]
let arr2 = [2, 3, 4]
let arr3 = ["2a", "3a", "4a"]
// first lets join arr2 and arr3 to a dictionary
var dict: [Int: String] = [:]
zip(arr2, arr3).forEach({ (pair) in
dict[pair.0] = pair.1
})
// and then just map each value in arr1 according to the dictionary, or provide a "No match" default
let result = arr1.map { (value) -> String in
return dict[value] ?? "No match"
}
print(result)
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