Regex to find exact word containing ampersand match in a string

Question

I want to find if "&1" (Exact) exists in a string or not with the help of Regular Expression. But I am not getting the correct result.

/\b\&1\b/i.test("Order Date is &1")

I am getting false result here. What is wrong?

Answer 1

简单一点：

 console.log(/(^|\\W)&1(\\W|$)/.test("Order Date is &1")) 

Answer 2

Since & is not alphanumeric, there is no "break" of an alphanumerical sequence between a space and & . So you may need the opposite of \\b , which is \\B :

 console.log(/\\B&1\\b/.test("Order Date is &1")); // true console.log(/\\B&1\\b/.test("Order Date is&1")); // false console.log(/\\B&1\\b/.test("&1 is the Order Date")); // true