google sheets script to remove rows based on dates in multiple cells

Question

I am working on an app to remove old content from a spreadsheet. I have found several posts that hide or delete sheets based on specific data, but it is always in a single cell. I need something that checks dates in three cells per row.

The sheet is populated by a form that asks users to enter three dates they want a bulletin to run in our video and print bulletin at the HS where I teach. I just want to remove old data, and found countless (well, maybe 6 or 8) examples of scripts that did something similar, so I grabbed one and tried to expand the logic statement to check columns C, D, and E (using index, of course).

It works, but removes any row with a date that is not today rather than dates in all three columns. I also need to have it count cells that are empty as qualifying as old.

So I tried the script suggested below by Cooper, which is a big advancement. It is still skipping rows with empty values, and in one case removes a row that I don't want to remove In the image shown a form accepts input from teachers who submit bulletin content for a maximum of three dates. I've formatted the sheet to show old dates in red, today in green, and future dates in yellow. I want to delete rows that have all red or empty cells. A bandaid, however, would be to force them to pick a date for all three rather than allow non entries. But it would be nice to have the code recognize blank cells as qualifying. [![Data Sheet for daily bulletin][1]][1]

Here's what eventually worked. I'm sure there are some smoother ways of doing this, but I actually grew a bit in my programming ability by working things out through the log first, then moving on once I had evidence that what I was doing worked.

 /* Here is the thinking: I need to have a script that is run from Add-ons that checks each cell of a range for dates. It can be done through conditional formatting bg colors, but that is redundant. The first thing is to create the functions that find and return row numbers that have all old dates. In the initial build these can be returned to the log (Logger.log()) inside of a for(loop). '*/ function readRows() { var sh=SpreadsheetApp.getActiveSheet(); var rg=sh.getDataRange(); var vA=rg.getValues(); var rowsDeleted=0; var today=new Date().valueOf(); //cycle through rows. In each row check column values for date. if date is old, add 1 to oldCount for(var i=vA.length-1;i>=0;i--) { var oldCount=0; if(new Date(vA[i][2]).valueOf()<today) { oldCount++; } if(new Date(vA[i][3]).valueOf()<today) { oldCount++; } if(new Date(vA[i][4]).valueOf()<today) { oldCount++; } if(oldCount>2) { sh.deleteRow(i+1); rowsDeleted++; } } Logger.log(rowsDeleted); } 

Next I want to figure out how to make something that will output the daily bulletin to a Doc or pdf.

Answer 1

Try this:

function readRows() {
  var sh=SpreadsheetApp.getActiveSheet();
  var rg=sh.getDataRange();
  var vA=rg.getValues();
  var rowsDeleted=0;
  var today=new Date().valueOf();
  for(var i=vA.length-1;i>=0;i--) {
    if ((new Date(vA[i][2]).valueOf()<today)||(new Date(vA[i][3]).valueOf()<today)||(new Date(vA[i][4]).valueOf()<today) ){
      sh.deleteRow(i+1);
      rowsDeleted++;
    }
  }
  Logger.log(rowsDeleted);
}

I'm not completely sure what you want but this might help. When your deleting rows you should start from the bottom.