I have the following:
a_list = [A,B,C]
r1 = range(1,5)
r2 = range(1,5)
r3 = range(1,5)
I would like to be able to find the various combinations of the elements in this list against the ranges. For example:
combi1 = [A, B, C, C, C]
combi2 = [A, A, B, C, C]
combi3 = [A, A, A, B, C]
combi4 = [A, B, B, C, C]
Etc.
I am able to do so if there were only 2 range
, but I'm not sure how to fit 3 range
in.
inc = range(1, 5)
desc = range(5, 1, -1)
combis = [list(itertools.chain(*(itertools.repeat(elem, n) for elem, n in zip(list, [i,j])))) for i,j in zip(inc,desc)]
SOLUTION:
def all_exist(avalue, bvalue):
return all(any(x in y for y in bvalue) for x in avalue)
combins = itertools.combinations_with_replacement(a_list, 5)
combins_list = [list(i) for i in combins]
for c in combins_list:
if all_exist(a_list, c) == True:
print c
output:
['A', 'A', 'A', 'B', 'C']
['A', 'A', 'B', 'B', 'C']
['A', 'A', 'B', 'C', 'C']
['A', 'B', 'B', 'B', 'C']
['A', 'B', 'B', 'C', 'C']
['A', 'B', 'C', 'C', 'C']
@doyz. I think this is may be what you are looking for :
From a list abc = ['A','B','C']
, you want to obtain its various combinations with replacement . Python has built-in itertools
to do this.
import itertools
abc = ['A', 'B', 'C'];
combins = itertools.combinations_with_replacement(abc, 5);
combins_list = [list(i) for i in combins];
print(combins_list[0:10]);
This is the first 10 combinations with replacement :
[['A', 'A', 'A', 'A', 'A'], ['A', 'A', 'A', 'A', 'B'], ['A', 'A', 'A', 'A', 'C'], \
['A', 'A', 'A', 'B', 'B'], ['A', 'A', 'A', 'B', 'C'], ['A', 'A', 'A', 'C', 'C'], \
['A', 'A', 'B', 'B', 'B'], ['A', 'A', 'B', 'B', 'C'], ['A', 'A', 'B', 'C', 'C'], ['A', 'A', 'C', 'C', 'C']]
If you want to include all elements in abc
, here is one way, that also includes the permutations :
import itertools
abc = ['A', 'B', 'C'];
combins = itertools.combinations_with_replacement(abc, 5);
combins_list = list(combins);
combins_all =[];
for i in combins_list:
if len(set(i))==len(abc):
combins_all.append(i);
print(combins_all);
include_permutations=[];
for i in combins_all:
permut = list(itertools.permutations(i));
include_permutations.append(permut);
print(include_permutations);
Is this okay?
*Note : itertools.combinations_woth_replacement
and itertools.permutations
do not result in a list, or tuple, but a different object itself, so you can't treat it as those.
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