PHP code with variables not UPDATING MySQL db
Question
I am a newbie-ish to MySQL/PHP (using XAMPP). I have tried every recommendation I have seen here for code but nothing seems to work....
I have a 3-column, 19 row table of textboxes (row1Field1, Row1, field2, row1Field3, etc.)
I am trying to UPDATE my database for those records where there will be records for each row (almost)
I KNOW THERE IS NO REAL SQL INJECTION PROTECTION. That is not an issue at this point. This is all opn my personal laptop & most likely will never see the Internet.
Here is my coe, 99% works everytime. The UPDATE does not.
<?php require '../connect/connect.php'; //connects the db (10 pages so far - all works
// Start the session
session_start();
$wk2Use = $_SESSION["wk2Use"];
?>
<html>
<body>
<?php
$f="";
$s=0;
$p=0;
for($i=1; $i <= 19; $i++) {
$f = "gm" . $i . "Fav";
$s = "gm" . $i . "Sprd";
$p = "gm" . $i . "Pts";
$f = htmlspecialchars($_POST[$f]);
$s = htmlspecialchars($_POST[$s]);
$p = htmlspecialchars($_POST[$p]);
if (!empty($f)) {
//This displays the correct data!
echo 'Wk-' . $wk2Use . ' ' . $f . ' ' . $s . ' ' . $p . '<br>';
//This does NOT work
$sql = ("USE bbschdefs; UPDATE bbschdefs SET sSchFav='".$f."', sSchSprd=$s, sSchOUPts=$p
WHERE ((sSchVTAbrv='".$f."' OR sSchHTAbrv='".$f."') AND schWk=$wk2Use )");
$result = mysqli_query($dbconn,$sql);
}
}
$i=0;
include '../predictions/predict.php'
?>
</body>
</html>
1 answers
solution1
0 2018-02-24 04:06:14
I'd have to guess it's because your variable $wk2Use is not properly being added to your where clause
WHERE ((sSchVTAbrv='".$f."' OR sSchHTAbrv='".$f."') AND schWk=$wk2Use )
Should be
WHERE ((sSchVTAbrv='".$f."' OR sSchHTAbrv='".$f."') AND schWk='{$wk2Use}' )
OR
WHERE ((sSchVTAbrv='".$f."' OR sSchHTAbrv='".$f."') AND schWk='".$wk2Use."' )
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