How to list directories and files in a Bash by script?

Question

I would like to list directory tree, but I have to write script for it and as parameter script should take path to base directory. Listing should start from this base directory.

The output should look like this:

Directory: ./a
File: ./a/A
Directory: ./a/aa
File: ./a/aa/AA
Directory: ./a/ab
File: ./a/ab/AB

So I need to print path from the base directory for every directory and file in this base directory.

UPDATED

Running the script I should type in the terminal this: ".\\test.sh /home/usr/Desktop/myDirectory" or ".\\test.sh myDirectory" - since I run the test.sh from the Desktop level. And right now the script should be run from the level of /home/usr/Dekstop/myDirectory"

I have the following command in my test.sh file:

find . | sed -e "s/[^-][^\/]*\//  |/g"

But It is the command , not shell code and prints the output like this:

DIR: dir1
    DIR: dir2
      fileA
    DIR: dir3
    fileC
fileB

How to print the path from base directory for every dir or file from the base dir? Could someone help me to work it out?

Answer 1

Not clear what you want maybe,

find . -type d -printf 'Directory: %p\n' -o -type f -printf 'File: %p\n'

However to see the subtree of a directory, I find more useful

find "$dirname" -type f

To answer comment it can also be done in pure bash (builtin without external commands), using a recursive function.

rec_find() {
    local f
    for f in "$1"/*; do
        [[ -d $f ]] && echo "Directory: $f" && rec_find "$f"
        [[ -f $f ]] && echo "File: $f"
    done
}

rec_find "$1"

Answer 2

You can use tree command. Key -L means max depth. Examples:

tree
.
├── 1
│   └── test
├── 2
│   └── test
└── 3
    └── test

3 directories, 3 files

Or

tree -L 1
.
├── 1
├── 2
└── 3

3 directories, 0 files

Answer 3

Create your test.sh with the below codes. Here you are reading command line parameter in system variable $1 and provides parameter to find command.

#!/bin/bash #in which shell you want to execute this script

find $1 | sed -e "s/[^-][^\/]*\//  |/g"

Now how will it work:-

./test.sh /home/usr/Dekstop/myDirectory #you execute this command

Here command line parameter will be assign into $1. More than one parameter you can use $1 till $9 and after that you have to use shift command. (You will get more detail information online).

So your command will be now:-

#!/bin/bash #in which shell you want to execute this script

find /home/usr/Dekstop/myDirectory | sed -e "s/[^-][^\/]*\//  |/g"  

Hope this will help you.