data test;
input ID month d_month;
datalines;
1 59 0
1 70 11
1 80 21
2 10 0
2 11 1
2 13 3
3 5 0
3 9 4
4 8 0
;
run;
I have two columns of data ID and Month. Column 1 is the ID, the same ID may have multiple rows (1-5). The second column is the enrolled month. I want to create the third column. It calculates the different between the current month and the initial month for each ID.
you can do it like that.
data test;
input ID month d_month;
datalines;
1 59 0
1 70 11
1 80 21
2 10 0
2 11 1
2 13 3
3 5 0
3 9 4
4 8 0
;
run;
data calc;
set test;
by id;
retain current_month;
if first.id then do;
current_month=month;
calc_month=0;
end;
if ^first.id then do;
calc_month = month - current_month ;
end;
run;
Krs
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