I am trying to convert category links from queries to Pretty URL's.
For Example, I have category 'ALASKA'. It's URL is https://www.mywebsite.com/category/alaska/
I am getting some queries from the url using following link: https://www.mywebsite.com/category/alaska/?subscriber=1
I want to convert this URL to Pretty URL ( https://www.mywebsite.com/category/alaska/subscriber/
) and also want to display custom template for it.
I tried this code:
Try 1
function my_template() {
if ( is_archive() ) {
if ( isset( $_REQUEST['subscriber'] ) ) {
$myurl = get_category_link();
if (substr($myurl) != "/") $myurl .= "/";
$myurl .= "subscriber/";
$myurl .= trim( sanitize_title_for_query( $_REQUEST['subscriber'] ) ) . "/";
exit( wp_redirect( $myurl ) ) ;
}
}
}
add_action( 'template_redirect', 'my_template_redirect' );
Above code didn't work for me.
I don't have enough knowledge about URL Rewriting in WordPress.
Please help me.
UPDATE:
Try 2:
As mentioned in comment by Oussama I came up with this code:
function wallpaperinho_subcat_rewrite_rule() {
add_rewrite_rule('^category/([^/]*)/subscriber/?','index.php?page_id=305965&subscriber=1','top');
}
add_action('init', 'wallpaperinho_subcat_rewrite_rule', 10, 0);
The above function works, but I am not able to detect current category ID on the custom page and in the function. Is there any way to do it? So I can display different data with different categories.
url = "https://www.mywebsite.com/category/alaska/?subscriber=1"
pretty = ""
for char in url: ## Loop through every letter in the 'ugly' URL
if char in "abcedfghijklmnopqrstuvwxyz./:": ## If the character is allowed
pretty += char ## Add it to the Pretty URL
EDIT: Just realised that your code is in PHP ... this code is in Python :( ... I'm working on a PHP version.
我不确定WordPress,您要寻找的是使用.htaccess
或Apache
配置重写URL。
You can make the link SEO friendly using .htaccess
RewriteRule ^category/([a-zA-Z0-9]+)/([a-zA-Z0-9]+)/?$ category/$1/?subscriber=$2 [NC,L]
And then you can retrieve your var subscriber value using $_GET['subscriber']
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