How to display images to html file using jquery? (some php and xml)

Question

I have a folder with images called " LaptopsImages ".

In my file called laptops.php i have an array list with different laptops with variables like: title, brand, price, description, spec and pictures names. My array list is convert to XML DOM tree.

On my file called product.html i wrote a code that take every product data into the variables and display it:

var title = $theProduct.find('title').text();
var brand = $theProduct.find('brand').text();
var price = $theProduct.find('price').text();
var description = $theProduct.find('description').text();
var spec = $theProduct.find('spec');
var imageFilename = $theProduct.find('picture').text();

document.getElementById("title").innerHTML=title
document.getElementById("brand").innerHTML=brand
document.getElementById("price").innerHTML=price                        
document.getElementById("description").innerHTML=description
document.getElementById("spec").innerHTML=description

I have accomplished to display every product data into my html except the pictures for each laptop. Is any way that i can display pictures with the name they have already from my variable? Assume that the pictures have names " 0001.jpg , 0002.jpg " and so on.

Every picture can be taken from: var imageFilename=$theProduct.find('picture').text();

Answer 1

document.getElementById("picture").src = imageFilename

如果有带有 id picture的<img>标签

Answer 2

如果您使用 jquery，您可以执行以下操作：

$("#picture").attr("src", imageFilename);

Answer 3

document.getElementById('myImage').src = imageFileName;

If you need the name from the ImageFileName then you can use:

name= imageFileName.substring(0, imageFileName.length - 4);/*to chop off .JPG*/

With Jquery:

$("#myImage").attr("src", imageFilename);

Answer 4

document.getElementById("price").innerHTML= "<img src=\"" + imageurl+ "\">";

您可以使用此代码在内部 div 中显示完整图像，其中 div id 是价格