I have an table on MySQL
tb_currencies
currencyid | currency_name
CU0001 | IDR
CU0002 | SGD
CU0003 | USD
tb_currency_converters
currencyconverterid | currency_month | from_currencyid_fk | to_currencyid_fk | amount
CC0001 | 2018-03-01 | CU0001 | CU0002 | 0.00009
CC0002 | 2018-03-01 | CU0002 | CU0001 | 10425
CC0003 | 2018-03-01 | CU0003 | CU0002 | 1.31964
tb_budgets
budgetid | budget_month | departmentid_fk | currencyid_fk
BU201803000001 | 2018-03-01 | DP0003 | CU0002
BU201803000002 | 2018-03-01 | DP0002 | CU0002
tb_items
itemid | item_name | currencyid_fk | price
IT0001 | Mouse | CU0001 | 165000
IT0002 | Keyboard | CU0002 | 20
IT0003 | TV LCD | CU0003 | 350
tb_pro_request
requestid | budgetid_fk | itemid_fk | quantity
RQ201803000001 | BU201803000001 | IT0002 | 1
RQ201803000002 | BU201803000001 | IT0003 | 5
RQ201803000003 | BU201803000001 | IT0004 | 1
Example:
My departmentid_fk
is: DP0003
, means I have Budget with Currency SGD
.
On tb_pro_request , there are 2 items transaction different currency(IDR & USD) with Budget Department Currency(SGD).
What I want is, that 2 items with different currency need to convert first to SGD
(Due to my Department Budget is: SGD) then SUM
it.
*Logic, if the currency is SGD
then no need to convert, but if not SGD
then convert it first using tb_currency_converters
then SUM
it.
Is it possible to do in directly to query?
My query code so far:
SELECT
R.requestid,
R.budgetid_fk,
R.category,
R.itemid_fk,
SUM(R.quantity),
R.request_date,
R.investmentid_fk,
R.remarks,
R.approval_status,
I.itemid,
I.item_name,
I.price,
SUM(R.quantity) * I.price as total,
B.budgetid,
B.budget_month
FROM
tb_pro_request R,
tb_items I,
tb_budgets B
WHERE
R.itemid_fk = I.itemid AND
R.budgetid_fk = B.budgetid AND
R.investmentid_fk = '' AND
B.active = 'Y' AND
(R.approval_status = 'P' OR R.approval_status = 'A') AND
DATE_FORMAT(B.budget_month,'%Y-%m') = '2018-03' AND
B.departmentid_fk = 'DP0003'
GROUP BY I.currencyid_fk
You can see there are 3 items with different currency below. What I want, convert to SGD for currency IDR, USD. then SUM it(to be 1 row)
I think I mess up a bit in your FK, but at least you have the spirit ;)
MySQL 5.6 Schema Setup :
Query 1 :
SELECT
R.budgetid_fk,
SUM(R.quantity),
SUM(R.quantity * I.price * COALESCE(CC.amount,1)) as total,
B.budgetid,
B.budget_month
FROM tb_pro_request R
INNER JOIN tb_items I
ON R.itemid_fk = I.itemid
INNER JOIN tb_budgets B
ON R.budgetid_fk = B.budgetid
AND B.active = 'Y'
LEFT JOIN tb_currency_converters CC
ON CC.from_currencyid_fk = I.currencyid_fk
AND CC.to_currencyid_fk = B.currencyid_fk
WHERE
R.investmentid_fk = ''
AND (
R.approval_status = 'P'
OR R.approval_status = 'A'
)
AND DATE_FORMAT(B.budget_month,'%Y-%m') = '2018-03'
AND B.departmentid_fk = 'DP0003'
GROUP BY R.budgetid_fk
Results :
| budgetid_fk | SUM(R.quantity) | total | budgetid | budget_month |
|----------------|-----------------|-------------------|----------------|--------------|
| BU201803000001 | 7 | 575.2840143424692 | BU201803000001 | 2018-03-01 |
Your query is invalid SQL, because you are aggregating the data and still show unaggregated columns, such as the requestid
. Which requestid
? There can be several.
The following groups by budget currency. If department_fk
plus budget_month
are unique in the table tb_budgets
, then we are selecting just a single one and can hence remove the GROUP BY
clause.
select
sum(i.price * r.quantity * coaleasce(cc.amount, 1)) as total,
c.currency_name
from tb_budgets b
join tb_pro_request r on r.budgetid_fk = b.budgetid
and r.approval_status in ('P','A')
and r.investmentid_fk = ''
join tb_items i on i.itemid = r.itemid_fk
join tb_currencies c on c.currencyid = b.currencyid_fk
left join tb_currency_converters cc on cc.currency_month = b.budget_month
and cc.from_currencyid_fk = i.currencyid_fk
and cc.to_currencyid_fk = b.currencyid_fk
where b.departmentid_fk = 'DP0003'
and date_format(b.budget_month,'%Y-%m') = '2018-03'
and b.active = 'Y'
group by c.currency_name;
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