I used Pandas to load a CSV to the following DataFrame:
value values
0 56.0 [-0.5554548,10.0748005,4.232949]
1 72.0 [-0.1953888,0.15093994,-0.058532715]
...
Now I would like to replace "values" column with 3 new columns like so:
value values_a values_b values_c
0 56.0 -0.5554548 10.0748005 4.232949
1 72.0 -0.1953888 0.15093994 -0.058532715
...
How can I split the list to 3 columns?
You can use split
with removing []
by strip
:
df1 = df.pop('values').str.strip('[]').str.split(',',expand=True).astype(float)
df[['values_a', 'values_b', 'values_c']] = df1
Solution if There is no NaN
s:
L = [x.split(',') for x in df.pop('values').str.strip('[]').values.tolist()]
df[['values_a', 'values_b', 'values_c']] = pd.DataFrame(L).astype(float)
solutions with converting columns first to list and then is used DataFrame
constructor:
import ast
s = df.pop('values').apply(ast.literal_eval)
df[['values_a', 'values_b', 'values_c']] = pd.DataFrame(s.values.tolist()).astype(float)
Similar:
df = pd.read_csv(file converters={'values':ast.literal_eval})
print (df)
value values
0 56.0 [-0.5554548, 10.0748005, 4.232949]
1 72.0 [-0.1953888, 0.15093994, -0.058532715]
df1 = pd.DataFrame(df.pop('values').tolist()).astype(float)
df[['values_a', 'values_b', 'values_c']] = df1
Final :
print (df)
value values_a values_b values_c
0 56.0 -0.555455 10.074801 4.232949
1 72.0 -0.195389 0.150940 -0.058533
EDIT:
If is possible in some column is more as 3 value then is not possible assign to 3 new columns. Solution is use join
:
df = df.join(df1.add_prefix('val'))
print (df)
value val0 val1 val2
0 56.0 -0.555455 10.074801 4.232949
1 72.0 -0.195389 0.150940 -0.058533
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