Implementing generic interface without specifying generic class

Question

I want to create generic interface and dont specify generic class when I implement this interface

public interface IThis<T>
{
    T this[int id] { get; }
}

public class Student : IThis<Student> // i dont want repeat Student in this
{
    public Student this[int id]
    {
        get => new Student();
    }
}

Answer 1

You can't omit the explicit type argument; C# won't let you. You must specify a type argument for every type variable that appears in a generic supertype.

A type variable (also called a generic parameter ) is a placeholder for some other type that will be specified when instantiating or implementing a generic type. The compiler won't infer the type arguments for you—at least not in a type declaration.