I have problem when I click on button the table row is not deleted tr id and button id are both same value. please tell where I am doing wrong
<tr id="<?php echo $result->id;?>">
<td><input type="text" name="feature[]" class="text-input medium-input datepickur" value="<?php echo $result->feature;?>" /></td>
<td><button type="button" name="remove" id="<?php echo $result->id;?>" class="btn btn-danger button_remove">X</button></td>
</tr>
Jquery code
$(document).ready(function() {
$('.button_remove').click(function() {
var btn_id = $(this).attr("id");
$('#' + btn_id + '').remove();
});
});
Thanks in advance
id
need to be unique per element if you are going to use them in jQuery
, and hense your code is not working (As tr
and td
sharing same value for id
).
Simplify you code through closest()
$(document).ready(function(){
$('.button_remove').click(function(){
$(this).closest('tr').remove();
});
});
Note:- Remove id
from tr
and td
both. As it's not needed at all. It will make your HTML
structure correct and cleaner.
Thats because you are using same id for tr
and button
....Try to use data-attributes
here
<tr id="<?php echo $result->id;?>">
<td><input type="text" name="feature[]" class="text-input medium-input datepickur" value="<?php echo $result->feature;?>" /></td>
<td><button type="button" name="remove" data-row="<?php echo $result->id;?>" class="btn btn-danger button_remove">X</button></td>
<tr>
And then use jQuery like this
$(document).ready(function() {
$('.button_remove').click(function() {
var btn_id = $(this).data("row");
$('#' + btn_id + '').remove();
});
});
$(document).ready(function() { $('.button_remove').click(function() { $(this).parents().eq(1).remove(); }); });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table> <tr> <td><input type="text" value="1"/></td> <td><button type="button" class="button_remove">X</button></td> </tr> <tr> <td><input type="text" value="2"/></td> <td><button type="button" class="button_remove">X</button></td> </tr> </table>
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