This is my input structure. All the fields here are optional because it can have zero or more elements in this json string. I am fine to use liftweb or regular scala.
{
"fname" : String,
"lname" : String,
"age" : String,
"gender" : String,
"phone" : String,
"mstatus" : String
}
Input: (Note here "mstatus" is not available and "gender" is empty)
{
"fname" : "Thomas",
"lname" : "Peter",
"age" : "20",
"gender" : "",
"phone" : "12345
}
I want to read this Json string and to check whether the key is present and its value is not null then add into a map. My output map would like below.
val inputMap = Map(
"fname" -> "Thomas"
"lname" -> "Peter"
"age" -> "20",
"phone" -> "12345)
Hope this can help you.
scala> val jsonString = """{
"fname" : "Thomas",
"lname" : "Peter",
"age" : "20",
"gender" : "",
"phone" : "12345"
}"""
jsonString: String =
{
"fname" : "Thomas",
"lname" : "Peter",
"age" : "20",
"gender" : "",
"phone" : "12345"
}
scala> val r = JSON.parseFull(jsonString)
.getOrElse(Map[String,Any]())
.asInstanceOf[Map[String,Any]].collect{
case e : (String, Any) if(e._2 != null && !e._2.toString.isEmpty) => e
}
r: scala.collection.immutable.Map[String,Any] = Map(fname -> Thomas, age -> 20, lname -> Peter, phone -> 12345)
You can use the Spary Json lib to convert and handle easy way.
val jsonString: String =
"""{
| "fname" : "Thomas",
| "lname" : "Peter",
| "age" : "20",
| "gender" : "",
| "phone" : "12345"
|}""".stripMargin
parse the json and get the map key value like this,
import spray.json._
val jsonMapKeyVal: Map[String, String] =
jsonString.parseJson
.asJsObject
.fields
.map {
case (k, JsString(v)) => k -> v
}
.filter(_._2!="")
Result:
Map(fname -> Thomas, age -> 20, lname -> Peter, phone -> 12345)
Reference: https://github.com/spray/spray-json
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